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9p^2-8p-1=0
a = 9; b = -8; c = -1;
Δ = b2-4ac
Δ = -82-4·9·(-1)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-10}{2*9}=\frac{-2}{18} =-1/9 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+10}{2*9}=\frac{18}{18} =1 $
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